Question

9.7545 gram of a substance occupies 3.12cm cube. express its density by keeping the significant figures

Answer 1

Task. 9.7545 gram of a substance occupies $3.12\ cm^{3}$. Express its density by keeping the significant figures.

Solution. The density of a substance of mass $m$ having volume $V$ is equal to

$\rho=\frac{m}{V}.$

In our case $m=9.7545$ and $V=3.12\ cm^{3}$, whence

$\rho=\frac{9.7545}{3.12}\approx 3.1264\approx 3.13\ g/cm^{3}$

Answer. $\rho\approx 3.13\ g/cm^{3}$