A motorcycle drives from A to B with a uniform speed of 30km/h and return back with a speed of 20km/h. Find the average speed
Solution:
Let vavg-average speed.
Let v1=30hkm,v2=20hkm
Let S – distance from A to B
Time taken from A to B is t1=v1S
Time taken from B to A is t2=v2S
Total distance travelled is: 2S
So
vavg=v2S+v2S2S=2v1+v2v1v2=24 km/h
Answer: 24 km/h