Question #33486

A motorcycle drives from A to B with a uniform speed of 30 km/h and return back with a speed of 20 km/h. Find the average speed

Expert's answer

A motorcycle drives from A to B with a uniform speed of 30km/h30\mathrm{km/h} and return back with a speed of 20km/h20\mathrm{km/h}. Find the average speed

Solution:

Let vavgv_{avg}-average speed.

Let v1=30kmh,v2=20kmhv_{1} = 30\frac{km}{h}, v_{2} = 20\frac{km}{h}

Let S – distance from A to B

Time taken from A to B is t1=Sv1t_1 = \frac{S}{v_1}

Time taken from B to A is t2=Sv2t_2 = \frac{S}{v_2}

Total distance travelled is: 2S

So


vavg=2SSv2+Sv2=2v1v2v1+v2=24 km/hv_{avg} = \frac{2S}{\frac{S}{v_2} + \frac{S}{v_2}} = 2\frac{v_1 v_2}{v_1 + v_2} = 24\ \mathrm{km/h}


Answer: 24 km/h24\ \mathrm{km/h}

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