The velocity of a particle is v=v0[1-sin(xt/T)]. Knowing that the particle starts from the origin with an initial velocity vo, determine (a) its position and its acceleration at t = 3T, (b) its average velocity during the interval t = 0 to t = T.
a(T)=v′=−πTv0cosπtT,a(T)=v'=-\frac{\pi}T v_0\cos\frac{\pi t}T,a(T)=v′=−Tπv0cosTπt,
a(3T)=πv0T.a(3T)=\frac{\pi v_0}T .a(3T)=Tπv0.
<v>=∫0TvdtT=v0(1−2π).<v>=\frac{\int_0^Tvdt}T=v_0(1-\frac 2{\pi}).<v>=T∫0Tvdt=v0(1−π2).
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