Answer to Question #333386 in Mechanics | Relativity for david

Question

a 0.40-kilogram mass is sliding on a horizontal friction less air track with a speed of 6.0 meters per second when it instantaneously hits and sticks to a 2.6-kilogram mass initially at rest on the track. The 2.6-kilogram mass is connected to one end of a mass less spring, which has a spring constant of 200 newtons per meter. The other end of the spring is fixed.

Answer 1

$l=\frac{(m_1+m_2)v^2}{2F}=1.2~m.$