Roger is travelling with a speed of 0.800c relative to Mia. Roger travels for 50.0 s as measured on his watch.
Calculate the elapsed time on Mia’s watch during this motion.
c = 3.0 ×
108
t=t01−v2c2=83 s.t=\frac{t_0}{\sqrt{1-\frac{v^2}{c^2}}}=83~s.t=1−c2v2t0=83 s.
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