Question #329010

A bicycle has a momentum of 24 kg m/s. What momentum would the bicycle have if it had…


… twice the mass and was moving at the same speed?

Answer 1


… the same mass and was moving with one-half the speed?

Answer 2


… three times the mass and was moving with twice the speed?

Answer 3


… one-half the mass and was moving with twice the speed?

Answer 4


… the same mass and was moving with twice the speed?

Answer 5


… three times the mass and was moving with one-half the speed?


1
Expert's answer
2022-04-15T16:40:16-0400

The momentum equals:

p=mv.p=mv.


If the bicycle had twice the mass and was moving at the same speed:

m=2m, v=v.m'=2m,\space v'=v.

p=mv=2mv=2p=224=48 kgm/s.p'=m'v'=2mv=2p=2\cdot 24=48\space kg\cdot m/s.

Answer 1: 48 kgm/s.48\space kg\cdot m/s.


If the bicycle had the same mass and was moving with one-half the speed?

m=m, v=v/2.m'=m,\space v'=v/2.

p=mv/2=p/2=24/2=12 kgm/s.p'=m\cdot v/2=p/2=24/2=12\space kg\cdot m/s.

Answer 2: 12 kgm/s.12\space kg\cdot m/s.


If the bicycle had three times the mass and was moving with twice the speed?

m=3m, v=2v.m'=3m,\space v'=2v.

p=3m2v=6mv=6p=624=144 kgm/s.p'=3m\cdot 2v=6mv=6p=6\cdot 24=144\space kg\cdot m/s.

Answer 3: 144 kgm/s.144\space kg\cdot m/s.


If the bicycle had one-half the mass and was moving with twice the speed?

m=m/2, v=2v.m'=m/2,\space v'=2v.

p=(m/2)2v=mv=p=24 kgm/s.p'=(m/2)\cdot 2v=mv=p=24 \space kg \cdot m/s.

Answer 4: 24 kgm/s.24 \space kg \cdot m/s.


If the bicycle had the same mass and was moving with twice the speed?

m=m, v=2v,m'=m,\space v'=2v,

p=m2v=2mv=2p=224=48 kgm/s.p'=m\cdot 2v=2mv=2p=2\cdot 24=48 \space kg\cdot m/s.

Answer 5: 48 kgm/s48 \space kg\cdot m/s


If the bicycle had three times the mass and was moving with one-half the speed?

m=3m, v=v/2.m'=3m,\space v'=v/2.

p=3mv/2=(3/2)mv=(3/2)p=(3/2)24=36 kgm/sp'=3m\cdot v/2=(3/2)mv=(3/2)p=(3/2)\cdot 24=36\space kg\cdot m/s.

Answer 6: 36 kgm/s36\space kg\cdot m/s


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