A 2 kg rectangular thin plate has a length of 0.5 m and a width of 0.20. the moment of inertia
of the plate is 0.29 kg-m2
. Where is the location of the axis of rotation?
I0=m(a2+b2)12=I6,I_0=\frac{m(a^2+b^2)}{12}=\frac I6,I0=12m(a2+b2)=6I,
I=6I0=I0+md2,I=6I_0=I_0+md^2,I=6I0=I0+md2,
md2=5I0=56I,md^2=5I_0=\frac 56I,md2=5I0=65I,
d=5I6m=0.35 m.d=\sqrt\frac{5I}{6m}=0.35~m.d=6m5I=0.35 m.
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