How large a force parallel to a 300 incline is needed to give a 5.0 kg an acceleration 0.20 m/s2 up the incline a) if friction is negligible? b) if the coefficient is 0.30?
a)
F=m(a+gsin30°)=26 N.F=m(a+g\sin30°)=26~N.F=m(a+gsin30°)=26 N.
b)
F=m(a+gsin30°+μgcos30°)=39 N.F=m(a+g\sin30°+\mu g\cos30°)=39~N.F=m(a+gsin30°+μgcos30°)=39 N.
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