Answer to Question #327596 in Mechanics | Relativity for soph

Question #327596

A bicycle has a kinetic energy of 124 J. What kinetic energy would the bicycle have if it had …


… three times the mass and was moving with one-half the speed?

Answer 1


… twice the mass and was moving at the same speed?

Answer 2


… the same mass and was moving with twice the speed?

Answer 3


… one-half the mass and was moving with twice the speed?

Answer 4


… the same mass and was moving with one-half the speed?


1
Expert's answer
2022-04-12T11:30:19-0400

The equation for kinetic energy:


E=mv22.E=\frac{mv^2}{2}.


If bicycle had three times the mass and was moving with one-half the speed?

m=3m, v=v2.m'=3m,\space v'=\frac{v}{2}.

E=mv22=3mv224=34E=34124=93 J.E'=\frac{m'v'^2}{2}=\frac{3mv^2}{2\cdot 4}=\frac{3}{4}E=\frac{3}{4}124=93\space J.

Answer 1: 93 J


If bicycle had twice the mass and was moving at the same speed?

m=2m, v=v.m'=2m, \space v'=v.

E=mv22=2mv22=2E=2124=248 J.E'=\frac{m'v'^2}{2}=\frac{2mv^2}{2}=2E=2\cdot124=248\space J.

Answer 2: 248 J


If bicycle had the same mass and was moving with twice the speed?

m=m, v=2v.m'=m, \space v'=2v.

E=mv22=m4v22=4E=2124=496 J.E'=\frac{m'v'^2}{2}=\frac{m\cdot 4v^2}{2}=4E=2\cdot124=496\space J.

Answer 3: 496 J

If bicycle had one-half the mass and was moving with twice the speed?

m=m2, v=2v.m'=\frac{m}{2}, \space v'=2v.

E=mv22=m4v222=2E=2124=248 J.E'=\frac{m'v'^2}{2}=\frac{m\cdot 4v^2}{2\cdot 2}=2E=2\cdot124=248\space J.

Answer 4: 248 J




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