Answer to Question #324663 in Mechanics | Relativity for Nikki

Question

Student drops a ball from a building and it takes 3 seconds to reach the ground. What was its speed before hitting the ground?

Answer 1

The speed of the ball before it hitting the ground:

$v=v_0+gt,$

where $v_0=0$ - the initial speed;

g - gravitational acceleration;

t - time.

So,

$v=0+9.8\cdot 3=29.4\space m/s.$