Question

A person throws a 755 g ball up at an angle such that it has an initial speed of 15.0 m s−1. After a short time the ball has a speed of 5.30 m s−1.

How much higher is the ball than when it was let go? (in m to 3 s.f)

(note: use g = 9.81 m s−2)

Answer 1

$h=\frac{v_0^2-v^2}{2g}=10.036~m.$