A spring with a spring constant of 6.2 N m−1 is used to launch a 5.0 g slider along a frictionless track as shown in the figure above. The spring is compressed by 16 cm.
To what height h above the height labeled 0 m in the figure does the slider reach? (in m to 2 s.f)
Answer
Using energy conservation
So height
"H=\\frac{0.5kx^2}{mg}\\\\=\\frac{0.5*6.2*0.16*0.16}{0.005*9.81}\\\\=0.16m"
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