Three resistors R1=2.0Ω, R2=12.0Ω, and R3=8.0Ω are connected in series with a 9.0-V battery. (a) Show the illustration (b) Calculate the current in the circuit and show that the sum of all voltage changes around the circuit is zero.
R=R1=R2+R3=22 Ω,R=R_1=R_2+R_3=22~\Omega,R=R1=R2+R3=22 Ω,
I=UR=400 mA.I=\frac UR=400~mA.I=RU=400 mA.
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