Find the diameter of an 18 m (L) long steel wire that will stretch no more than 9 mm(∆L) when a load (stress) of 3800 N is hung on the end of the wire. The Young’s Modulus for steel wire is 200 x 109 N/m2
ΔLL=FSE=Fπr2E,\frac{\Delta L} L=\frac{F}{SE}=\frac F{\pi r^2E},LΔL=SEF=πr2EF,
d=2FLπEΔL=7 mm.d=2\sqrt{\frac{FL}{\pi E\Delta L}}=7~mm.d=2πEΔLFL=7 mm.
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