Juan pulls the sled with a force of 255 N moving horizontally 10.00 m.
what is the work done by Juan on the sled
Mechanical work is calculated by the formula W=FsW = FsW=Fs
In this case F=255NF = 255NF=255N and s=10ms = 10ms=10m
We have: W=255N⋅10m=2550J=2.55kJW = 255N \cdot 10m = 2550J = 2.55kJW=255N⋅10m=2550J=2.55kJ
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