Question #323176

when hit, the velocity of a 0.2 kg baseball changes from +25m/s to -25m/s. what is the magnitude of the impulse delivered by the bat to the ball?


1
Expert's answer
2022-04-04T09:03:40-0400

Explanations & Calculations


  • You can just apply the formula for the impulse to solve this question.
  • Use the sign convention properly.

(+)I=Δ(mv)=mΔv=m[v(+v)]=2mv=2×0.2kg×25ms1=10Nm\qquad\qquad \begin{aligned} \to(+)\\ \small I&=\small \Delta(mv)\\ &=\small m\Delta v\\ &=\small m[-v-(+v)]\\ &=\small -2mv\\ &=\small -2\times0.2\,kg\times25\,ms^{-1}\\ &=\small -10\,Nm \end{aligned}

  • Since the impulse gets a negative value along the previously considered direction, this means the impulse is otherway around: along the direction of the final velocity(back).

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