Question #322772

1.   Calculate the kinetic energy and momentum of a proton traveling 2.90 π‘₯ 108 π‘š/𝑠.



1
Expert's answer
2022-04-04T09:05:50-0400

The relativistic kinetic energy of a proton is

K=1(1βˆ’(vc)2)mc2K=\frac{1}{\sqrt(1-(\frac{v}{c})^2)} mc^2

=1(1βˆ’(2.90Γ—1083Γ—108)2)(938MeV)=3663.5MeV=\frac{1}{\sqrt(1-(\frac{2.90 \times10^8}{3 \times10^8})^2)} (938 MeV) =3663.5 MeV

The relativistic momentum of a proton is

p=1(1βˆ’(vc)2)mvp=\frac{1}{\sqrt(1-(\frac{v}{c})^2)} mv

=1(1βˆ’(2.90Γ—1083Γ—108)2)(938MeV/c2)(2.90Γ—1083Γ—108)c=\frac{1}{\sqrt(1-(\frac{2.90 \times10^8}{3 \times10^8})^2)} (938 MeV/c^2)(\frac{2.90 \times10^8}{3 \times10^8})c

=35141.5MeV/c=35141.5 MeV/c


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