determine the precision of these two approximate values:
a) 3000. ft
b) 1.20 times 10(--5)ms
be careful, first write in std.dec.form
a)
"\\varepsilon_1=\u00b10.5~ft,"
b)
"\\varepsilon_2=\u00b10.5\\cdot 10^{-6}~ms."
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