Question #32101

2 trains A and B are moving in same direction at same track with B ahead of A with speed u and train A with speed v (v>u). the driver of A sees B and starts decelerating with 'a'. What is the min distance to avoid collision

Expert's answer

2 trains A and B are moving in same direction at same track with B ahead of A with speed u and train A with speed v (v>u). the driver of A sees B and starts decelerating with 'a'. What is the min distance to avoid collision?

Relative speed equals:


v12=(vat)uv _ {1 2} = (v - a t) - u

d0d_0 – initial distance, tt – time, aa – deceleration

min distance to avoid collision if v12=0d=0v_{12} = 0 \Rightarrow d = 0

v12=0t=vuav _ {1 2} = 0 \quad \Rightarrow \quad t = \frac {v - u}{a}


Distance between trains at moment of time t:


d=d0(vu)t+at22=d0(vu)22ad = d _ {0} - (v - u) t + \frac {a t ^ {2}}{2} = d _ {0} - \frac {(v - u) ^ {2}}{2 a}


min distance if d=0d = 0:


d0=(vu)22ad _ {0} = \frac {(v - u) ^ {2}}{2 a}


Answer: d0=(vu)22ad_0 = \frac{(v - u)^2}{2a}

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS