Question #32044

An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?

_____ ft/s

Expert's answer

Task. An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?

Solution. There is a gravitation force acting on the object. Therefore it moves with constant acceleration g=9.8  m/s2g=9.8\;m/s^{2}. Since it was dropped, its initial velocity is zero. Therefore its height at time tt is given by the formula:

h(t)=h0gt22,h(t)=h_{0}-\frac{gt^{2}}{2},

where h0=100h_{0}=100 feet is the initial height. We should find tt such that h(t)=0h(t)=0, that is

h0gt22=0h_{0}-\frac{gt^{2}}{2}=0

t2=2h0g.t^{2}=\frac{2h_{0}}{g}.

t=2h0g.t=\sqrt{\frac{2h_{0}}{g}}.

Notice that

1  foot=0.3048  m,1\;\mathrm{foot}=0.3048\;m,

so

h0=100  feet=304.8  m.h_{0}=100\;\mathrm{feet}=304.8\;m.

Therefore

t=2h0g=2304.89.8=609.69.8=62.204=7.88707.9  s.t=\sqrt{\frac{2h_{0}}{g}}=\sqrt{\frac{2*304.8}{9.8}}=\sqrt{\frac{609.6}{9.8}}=\sqrt{62.204}=7.8870\approx 7.9\;s.

Answer. 7.9 s.


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