A body moves from a position r²=(I + 2j –3k) meter under the influence of constant force F=( 3i +3–k) Newton. Calculate the work done by the force.
Answer
Work done is dot product of force and position
W=F.r=(3i+3j–k).(i+2j–3k)=3+6+3=12JW=F.r\\=( 3i +3j–k) .(i+ 2j –3k) \\=3+6+3\\=12JW=F.r=(3i+3j–k).(i+2j–3k)=3+6+3=12J
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