Answer to Question #319917 in Mechanics | Relativity for Jake

Question #319917

To avoid a potential collision with wildlife cross the road, the driver of a car traveling 105 km/h fully applies the brakes to stop as quickly as possible. If the car stops 3.8 s after the brakes are applied, what is the braking distance ?



1
Expert's answer
2022-03-29T05:33:46-0400

Explanations & Calculations


  • Since the deceleration is constant/ assumed constant / normally constant, one can apply s=(u+v)t2\small s = \large \frac{(u+v)t}{2} to calculate the distance travelled in time t.

105kmh1=105×10003600=29.17ms1s=(0+29.17)×3.8s2=55.4m\qquad\qquad \begin{aligned} \small 105\,kmh^{-1}&=\small \frac{105\times1000}{3600}=29.17\,ms^{-1}\\ \small s&=\small \frac{(0+29.17)\times3.8\,s}{2}\\ &=\small 55.4\,m \end{aligned}


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