Question #31973
an asteroid is 3 times as far from the sun as the earth. what is it's period
in earth years?
Solution
According to the third Kepler's law
"The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit."
P a s r t e r o i d 2 a a s t e r o i d 3 = P e a r t h 2 a e a r t h 3 \frac {P _ {\text {a s r t e r o i d}} ^ {2}}{a _ {\text {a s t e r o i d}} ^ {3}} = \frac {P _ {\text {e a r t h}} ^ {2}}{a _ {\text {e a r t h}} ^ {3}} a a s t e r o i d 3 P a s r t e r o i d 2 = a e a r t h 3 P e a r t h 2 P a s r t e r o i d = P e a r t h 2 ∗ a a s t e r o i d 3 a e a r t h 3 = P e a r t h a a s t e r o i d 3 a e a r t h 3 P _ {a s r t e r o i d} = \sqrt {\frac {P _ {e a r t h} ^ {2} * a _ {a s t e r o i d} ^ {3}}{a _ {e a r t h} ^ {3}}} = P _ {e a r t h} \sqrt {\frac {a _ {a s t e r o i d} ^ {3}}{a _ {e a r t h} ^ {3}}} P a sr t ero i d = a e a r t h 3 P e a r t h 2 ∗ a a s t ero i d 3 = P e a r t h a e a r t h 3 a a s t ero i d 3
Such as
a a s t e r o i d = 3 a e a r t h a _ {a s t e r o i d} = 3 a _ {e a r t h} a a s t ero i d = 3 a e a r t h P a s r t e r o i d = P e a r t h 3 3 P _ {a s r t e r o i d} = P _ {e a r t h} \sqrt {3 ^ {3}} P a sr t ero i d = P e a r t h 3 3 P a s r t e r o i d ≈ 5.2 P e a r t h ≈ 5.2 y e a r s P _ {a s r t e r o i d} \approx 5. 2 P _ {e a r t h} \approx 5. 2 y e a r s P a sr t ero i d ≈ 5.2 P e a r t h ≈ 5.2 ye a rs
Answer:
The period is 5.2 earth years. (5 years 73 days)