Question #31972

A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the value of work being done on the object

Expert's answer

Work is defined by the following formula:


A=FScos(α)A = F * S * \cos (\alpha)


where: F - force

S - displacement

α\alpha - the angle between the force and displacement

So, substituting given values, we obtain:


A=2550cos(40)=1250cos(40)=957.5958 JlA = 25 * 50 * \cos (40) = 1250 * \cos (40) = 957.5 \approx 958 \mathrm{~Jl}


Answer: 958 Jl

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