a block of 18kg is pushed along a horizontal frictionless surface by a horizontal force of 80N. the block start from rest. compute the kinetic energy after 6 seconds
a=Fm,a=\frac Fm,a=mF,
v=at=Ftm,v=at=\frac{Ft}m,v=at=mFt,
E=mv22=F2t22m=6.4 kJ.E=\frac{mv^2}2=\frac{F^2t^2}{2m}=6.4~kJ.E=2mv2=2mF2t2=6.4 kJ.
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