Question #317957

Derive the equation of motion of a simple harmonic motion and obtain the expression for its velocity time period and frequency

Expert's answer

x¨+kmx=0,\ddot x+\frac km x=0,

ω2=km,\omega^2={\frac km},

x¨+ω2x=0,\ddot x+\omega^2 x=0,

ω=km,\omega=\sqrt{\frac km},

T=2πω=2πmk.T=\frac{2\pi}{\omega}=2\pi\sqrt{\frac mk}.


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