Answer to Question #317957 in Mechanics | Relativity for Rahul rbk

Question #317957

Derive the equation of motion of a simple harmonic motion and obtain the expression for its velocity time period and frequency

1
Expert's answer
2022-03-25T09:11:03-0400

x¨+kmx=0,\ddot x+\frac km x=0,

ω2=km,\omega^2={\frac km},

x¨+ω2x=0,\ddot x+\omega^2 x=0,

ω=km,\omega=\sqrt{\frac km},

T=2πω=2πmk.T=\frac{2\pi}{\omega}=2\pi\sqrt{\frac mk}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment