Question

Determine the curl of F which is (∇ × F ) at the point (2, 0, 3) given that

F = ze2xy i + 2xz cosy j+ (x + 2y)k

Answer 1

$\text{curl}\vec F=(2-2x\cos y)\vec i+(e^{2xy}-1)\vec j+(2z\cos y-2xze^{2xy})\vec k,$

$\text{curl}\vec F(2,0,3)=-2\vec i-6\vec k.$