Question

An object of mass 4 kg is moved on a horizontal surface with a constant acceleration of 0.2m/s^2 , by a horizontal force of 6 Newtons. Find the friction force acting on the object and the coefficient of friction.

Answer 1

Net force

$F=ma$

Friction force

$F_1-F=F_f$

Coefficient of friction

$f=\frac{F_f}{R}$

$R=mg$

Calculating

$F_f=6-4\cdot 0.2=5.2$

$f=\frac{5.2}{4\cdot 10}=0.13$

Answer Friction force 5.2 newton, coefficient of friction 0.13