Question #313676

A man runs around a circular track of 800 meters radius for 30 seconds, starting at a point directly to the right of the center and goes in a counterclockwise manner. He goes 5 meters per second for the first 15 seconds, runs 90 meters for the next 6 seconds and then 180 meters for the rest of the course. What was his average speed?


1
Expert's answer
2022-03-20T18:50:29-0400

Explanations & Calculations


  • The total distance he would have covered during the course is

S=(5ms1×15s)+(90m)+(180m)=345m\qquad\qquad \begin{aligned} \small S&=\small (5\,ms^{-1}\times15\,s)+(90\,m)+(180\,m)\\ &=\small 345\,m \end{aligned}

  • Total time he would have taken is

t=30s\qquad\qquad \begin{aligned} \small t&=\small 30\,s \end{aligned}

  • Then the average speed would be

Avg.speed=Distancetime=345m30s=11.5ms1\qquad\qquad \begin{aligned} \small Avg.speed&=\small \frac{Distance}{time}\\ &=\small \frac{345\,m}{30\,s}\\ &=\small 11.5\,ms^{-1} \end{aligned}

  • He did not cover the whole circle (L=2π.800)\small L= 2\pi.800) during that time.

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