Question #31340

Skier is going downhill starting from rest and accelerating at a constant 2.0m/s squared. If it takes her 15 seconds to reach the bottom, what is the length of the slope?

Expert's answer

Task. Skier is going downhill starting from rest and accelerating at a constant a=2.0m/s2a=2.0\,m/s^{2}. If it takes her t=15t=15 seconds to reach the bottom, what is the length of the slope?

Solution. The skier moved with constant acceleration aa and initial velocity v0=0 m/sv_{0}=0\ m/s during time t=15 st=15\ s. The general formula for the distance passed by the skier has the following form:

d=v0t+at22.d=v_{0}t+\frac{at^{2}}{2}.

Substituting values we get that

d=v0t+at22=015+21522=225 m.d=v_{0}t+\frac{at^{2}}{2}=0*15+\frac{2*15^{2}}{2}=225\ m.

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