A stone is thrown from the ground upward with an initial velocity of 20 m/s
a- At what time the stone will reach the maximum height?
b- What is the maximum height the stone can reach ?
c- What is the height of the stone from the ground after 3 seconds ?
I solved ( A) and ( B) and I need answer for part ( C )
Answer
A- Vf = Vi + gt
0 = 20 + ( 9.8 m/s2) t
20 + 9.8t = 0
9.8 t = -20 so t = -20/9.8 m/s^2 = 2.04 second
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