Question

starting from rest a car accelerates at 2.0 m/s^2. How far will it go after 6.0 s

Answer 1

Explanations & Calculations

• Since the acceleration is constant apply $\small s=ut+1/2at^2$ for its motion.

$\qquad\qquad \begin{aligned} \small s&=\small 0+\frac{1}{2}\times2.0\,ms^{-2}\times(6.0\,s)^2\\ &=\small 36.0\,m \end{aligned}$