Question

A box of mass 500kg is druged along a level ground at a speed of 12metres per second.if the force of friction between the box and the floor is 1200newtons .calculate the power developed?

Answer 1

Explanations & Calculations

• Since the force needed to move the box is the same as the magnitude of the friction force under a uniform speed, the power which is given by $\small P= F.v$ can be easily evaluated.

$\qquad\qquad \begin{aligned} \small P&=\small 1200\,N\times12\,ms^{-1}=14400\,W \end{aligned}$