A man in a sled, with a total mass of 125 kg, slides down a grassy hill and reaches a speed of 8 m/s at the bottom. If a pile of grass can exert a constant force of 250 N, how fast will the sled stop?
Explanations & Calculations
F=maa=250 N125 kg=2 ms−2F=m(v−u)ΔtΔt=125 kg(0−8)−250 N=4 s\qquad\qquad \begin{aligned} \small F&=\small ma\\ \small a&=\small \frac{250\,N}{125\,kg}=2\,ms^{-2}\\ \\ \small F&=\small \frac{m(v-u)}{\Delta t}\\ \small \Delta t&=\small \frac{125\,kg(0-8)}{-250\,N}\\ &=\small 4\,s \end{aligned}FaFΔt=ma=125kg250N=2ms−2=Δtm(v−u)=−250N125kg(0−8)=4s
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment