Explanation & Calculations
a)
- Take the system as a whole so that only the two weights of the ball and the single thread is seen, and consider the equilibrium.
T−2mgT=0=294N
- If the two threads make θ angles with the horizontal (they are identical as the system is symmetrical about the vertical)
cosθsinθ=r+35.0r=12.5+35.012.5=0.263=0.945
- Now consider the equilibrium of a ball under the act of its weight and one of the two threads.
↑T1sinθ−mgT1=0=155.6N
b)
- Consider the horizontal equilibrium of a ball under the same act and say the force the balls are being pushed is R,
→T1cosθ−RR=0=40.9N
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