A gas occupies a certain volume at 27 degree Celsius. If it is heated at constant pressure, its volume is exactly doubled at a temperature of
Solution
Let's use the ideal gas law:
P∗V=v∗R∗T.
Where P is pressure of the gas, V is volume of the gas, T is temperature of the gas (in Kelvin), v is amount of substance of gas, R is the ideal gas constant.
Let assume T0=27∘C=(273+27)K=300K. As pressure P is constant, then
2∗P∗V=v∗R∗T1→T1=v∗R2∗P∗V=v∗R2∗(P∗V)=v∗R2∗v∗R∗T0=2∗T0.
So, the volume doubles when the temperature doubles. Here doubled temperature is
T1=2∗300K=600K=(600−273)∘C=327∘C.
Answer: 327∘C