Question #31183

A gas occupies a certain volume at 27 degree celcius.If it is heated at constant pressure, its volume is exactly doubled at a temperature of ----------------------

Expert's answer

A gas occupies a certain volume at 27 degree Celsius. If it is heated at constant pressure, its volume is exactly doubled at a temperature of

Solution

Let's use the ideal gas law:


PV=vRT.P * V = v * R * T.


Where PP is pressure of the gas, VV is volume of the gas, TT is temperature of the gas (in Kelvin), vv is amount of substance of gas, RR is the ideal gas constant.

Let assume T0=27C=(273+27)K=300KT_0 = 27{}^\circ C = (273 + 27)K = 300\,K. As pressure PP is constant, then


2PV=vRT1T1=2PVvR=2(PV)vR=2vRT0vR=2T0.2 * P * V = v * R * T_1 \rightarrow T_1 = \frac{2 * P * V}{v * R} = \frac{2 * (P * V)}{v * R} = \frac{2 * v * R * T_0}{v * R} = 2 * T_0.


So, the volume doubles when the temperature doubles. Here doubled temperature is


T1=2300K=600K=(600273)C=327C.T_1 = 2 * 300\,K = 600\,K = (600 - 273){}^\circ C = 327{}^\circ C.


Answer: 327C327{}^\circ C

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