Question #30994

How long will it take a car starting from rest to travel 659.0 km if its acceleration is 2.4 m/s/s?

Expert's answer

Task. How long will it take a car starting from rest to travel d=659.0d=659.0 km if its acceleration is a=2.4 m/s2a=2.4\ m/s^{2}?

Solution. The formula for the distance by time tt passed with constant acceleration has the following form:

d(t)=v0t+at22.d(t)=v_{0}t+\frac{at^{2}}{2}.

In our case the initial velocity v0=0v_{0}=0, so

d(t)=at22,d(t)=\frac{at^{2}}{2},

whence

t=2da.t=\sqrt{\frac{2d}{a}}.

We should find tt such that d=659 km =659000 md=659\ km\ =659000\ m and acceleration is a=2.4 m/s2a=2.4\ m/s^{2}. Substituting values we get:

t=2da=26590002.4=741.06 sek=741.0660min=12.35 min.t=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2*659000}{2.4}}=741.06\ sek=\frac{741.06}{60}min=12.35\ min.

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