Task. How long will it take a car starting from rest to travel d=659.0 km if its acceleration is a=2.4 m/s2?
Solution. The formula for the distance by time t passed with constant acceleration has the following form:
d(t)=v0t+2at2.
In our case the initial velocity v0=0, so
d(t)=2at2,
whence
t=a2d.
We should find t such that d=659 km =659000 m and acceleration is a=2.4 m/s2. Substituting values we get:
t=a2d=2.42∗659000=741.06 sek=60741.06min=12.35 min.