Question #309320

A KTM commuter train travels between two stations, A and B. The train starts from rest from station A and accelerates at a constant rate for 0.5 km until it reaches a speed of 30 m/s. It then travels at this constant speed for T s before decelerating at a constant rate of 1.5 m/s2 and coming to rest at station B. Figure 1 shows the velocity-time graph of the train’s journey between the two stations. Determine the value of T if the distance between the two stations 6 km. Calculate also the total time taken for the whole journey.

1
Expert's answer
2022-03-15T10:36:29-0400

d=ll1l2=lv22a1v22a2=4 km,d=l-l_1-l_2=l-\frac{v^2}{2a_1}-\frac{v^2}{2a_2}=4~km,

T=dv=133s,T=\frac d v=133^s,

t=T+4(lq)a1+a2=283s.t=T+\sqrt{\frac{4(l-q)}{a_1+a_2}}=283^s.


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