Question

An object weighing 58,800 N rests on the flatbed of a truck. It is held in place by metal brackets that can exert a maximum horizontal force of 9000 N. When the truck is traveling 15 m/s, what is the minimum stopping distance if the load is not to slide forward into the cab?

Answer 1

Solution.

$P=58800N;$

$F=9000N;$

$v0=15m/s;$

$P=mg\implies m=\dfrac{P}{g};$

$m=\dfrac{58800}{9.8}=6000kg;$

$F=ma\implies a=\dfrac{F}{m};$

$a=\dfrac{9000}{6000}=1.5 m/s;$

$S=\dfrac{v^2-v_0^2}{2a};$

$S=\dfrac{-225}{-3}=75m;$

Answer: $S=75m.$