Explanations & Calculations
40kmh−1=11.11ms−1
- The distance travelled during the reaction time
d=ut=11.11ms−1×0.25s=2.78m
- Then the distance remained to stop the car at the stated deceleration is
S=13m−2.78m=10.22m
- But the distance the car would travel during deceleration is
v20S1=u2+2as=(11.11ms−1)2+2(−8ms−2)×S1=7.7m
- Since the stopping distance is less than the actual remaining distance, the car stops before hitting.
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