Question #308946

The speed limit in a school zone is 40 km/hr. A driver traveling at this speed sees a child run onto the road 13 m ahead of his car. He applies the brakes, and the car decelerates at a uniform rate of 8 m/s². If the driver’s reaction time is 0.25 s, will the car stop before hitting the car?




1
Expert's answer
2022-03-10T18:01:21-0500

Explanations & Calculations


40kmh1=11.11ms1\qquad\qquad \begin{aligned} \small 40\,kmh^{-1} &=\small 11.11\,ms^{-1} \end{aligned}

  • The distance travelled during the reaction time

d=ut=11.11ms1×0.25s=2.78m\qquad\qquad \begin{aligned} \small d&=\small ut = 11.11\,ms^{-1}\times 0.25\,s = 2.78\,m \end{aligned}

  • Then the distance remained to stop the car at the stated deceleration is

S=13m2.78m=10.22m\qquad\qquad \begin{aligned} \small S = 13\,m-2.78\,m = 10.22\,m \end{aligned}

  • But the distance the car would travel during deceleration is

v2=u2+2as0=(11.11ms1)2+2(8ms2)×S1S1=7.7m\qquad\qquad \begin{aligned} \small v^2 &=\small u^2 +2as\\ \small 0&=\small (11.11\,ms^{-1})^2 +2(-8\,ms^{-2})\times S_1\\ \small S_1 &=\small 7.7\,m \end{aligned}


  • Since the stopping distance is less than the actual remaining distance, the car stops before hitting.

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