Question #308923

In order to get his car out of the mud, a man ties one end of a rope to the front bumper and

the other end to a tree 15 m away, as shown below. He then pulls on the center of the rope

with a force of 400 N, which causes its center to be displaced 0.30 m, as shown. What is the

force of the rope on the car?


1
Expert's answer
2022-03-10T10:17:25-0500

Answer

The magnitude of the force on the car from the rope is

T=F2sinθθ=tan1(F2T)θ=tan1(0.307.5)θ=2.29°T=\frac{F}{2sin\theta}\\\theta=tan^{-1}(\frac{F}{2T}) \\\theta=tan^{-1}(\frac{0.30}{7.5})\\\theta=2.29°

Now

So tension is

T=4002sin2.29°=5005.33NT=\frac{400}{2sin2.29°}\\=5005.33N





Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS