Question

the train ‘A’ travelled a distance of 120 km in 3 hours whereas another train ‘B’ travelled a distance of 180 km in 4 hours. Which train travelled faster?

Answer 1

Question 30858

Velocity for uniform (non-accelerated) motion can be calculated as $v = \frac{S}{t}$ , where $S$ is the distance, traveled in $t$ seconds. Hence:

The velocity of the train A is $v_{A} = \frac{120km}{3h} = 40\frac{km}{h}$ .

The velocity of the train B is $v_{B} = \frac{180km}{4h} = 42.5\frac{km}{h}$ .

Thus, since velocity of the train B is higher, it traveled faster.