Answer to Question #308525 in Mechanics | Relativity for Trooye

Question #308525

What is the power available in a weir jet having a cross-sectional area of 0.005m^2 with a velocity of 25.80m/sec?


1
Expert's answer
2022-03-10T18:02:10-0500

Power

P=QtP=\frac{Q}{t}

Q=AvQ=Av


Q=0.005×25.80=0.129m3/secQ={0.005\times25.80}=0.129m^3/sec

Power

P=0.129tWP=\frac{0.129}{t}W


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