Question #30850

A ball is thrown downward 8 m/s. What is its speed 4 seconds later?

Expert's answer

Task. A ball is thrown downward v=8v=8 m/s. What is its speed 4 seconds later?

Solution. Notice that there is a gravitation force acting on the ball, so it moves with constant acceleration g=9.8 m/s2g=9.8\ m/s^{2}. Therefore the speed of the ball after tt seconds is given by the formula:

v(t)=v0+gt,v(t)=v_{0}+gt,

where v0=8 m/sv_{0}=8\ m/s is the initial velocity.

We should compute v(4 s)v(4\ s). Substituting values we get:

v(4)=v0+gt=8+9.84=47.2 m/s.v(4)=v_{0}+gt=8+9.8*4=47.2\ m/s.

Answer. v=47.2 m/s.v=47.2\ m/s.

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