Question

A body having a net charge of 37 µC placed in a uniform electric field of 750 N/C. What is the mass of the body if it lies on the surface in the field?

Please give me the full solution, thank you so much.

Answer 1

We know that

$qE=ma$

$M=\frac{qE}{a}$

a=g

$$M=\frac{37\times10^{-6}\times750}{9.8}=2.84\times10^{-3}kg$$