Question #306978

1. a.) Suppose a hockey puck slides down a frictionless ramp with an acceleration of 5 m/s². What angle does the ramp make with respect to the horizontal?


b) If the ramp has a length of 6 m, how long does it take the puck to reach the bottom?


c) Now suppose the mass of the puck is doubled, What will be it’s acceleration?



2. A space-walking astronaut of total mass 148 kg exerts a force of 265 N on a free-floating satellite of mass 635 kg, pushing it in the +x direction.


a. What is the reaction force exerted by the satellite on the astronaut?


b. Calculate the acceleration of the astronaut


c.The acceleration of the satellite




1
Expert's answer
2022-03-10T10:18:38-0500

Explanations & Calculations


1.a)

  • Acceleration on a frictionless incline is given by a=gsinθ\small a = g\sin\theta, so using this we get the following.

5ms2=9.8ms2×sinθθ=30.70\qquad\qquad \begin{aligned} \small 5\,ms^{-2}&=\small 9.8\,ms^{-2}\times\sin\theta\\ \small \theta&=\small 30.7^0 \end{aligned}

b)

  • Use s=ut+1/2at2\small s = ut+1/2 at^2 along the incline downward.

6m=0+12×5ms2×t2t=1.5s\qquad\qquad \begin{aligned} \small 6\,m&=\small 0+\frac{1}{2}\times5\,ms^{-2}\times t^2\\ \small t&=\small 1.5\,s \end{aligned}

c)

  • The acceleration does not depend on mass so it remains unchanged.


2.a)

  • It is equal to the applied force of 265 N as it is the only force that exists in the given scenario.


b)

F=maa=265N148kg=1.8ms2\qquad\qquad \begin{aligned} \small F&=\small ma\\ \small a&=\small \frac{265\,N}{148\,kg}=1.8\,ms^{-2} \end{aligned}

c)

F=maa=265N635kg=0.4ms2\qquad\qquad \begin{aligned} \small F&=\small ma\\ \small a&=\small \frac{265\,N}{635\,kg}=0.4\,ms^{-2} \end{aligned}


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