Question #305480

Given two vectors A=6i + 3j - k and B = 4i -5j + 8k , find the magnitude of the vector 2A - 3B.

1
Expert's answer
2022-03-06T15:19:12-0500

A=6i^+3j^k^B=4i^5j^+8k^A=6\hat{i}+3\hat{j}-\hat{k}\\B=4\hat{i}-5\hat{j}+8\hat{k}

2A3B=2(6i^+3j^k^)3(4i^5j^+8k^)2A-3B=2(6\hat{i}+3\hat{j}-\hat{k})-3(4\hat{i}-5\hat{j}+8\hat{k})

2A3B=0i^+21j^26k^2A-3B=0\hat{i}+21\hat{j}-26\hat{k}

Magnitude of vector


2A3B=02+212+(26)2=1117=33.42|2A-3B|=\sqrt{0^2+21^2+(-26)^2}=\sqrt{1117}=33.42


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