Question

Suppose you adjust your garden hose nozzle for a fast stream of water. You point the nozzle vertically upward at a height of 1.8 m above the ground (. When you quickly turn off the nozzle, you hear the water striking the ground next to you for another 2.6 s .

What is the water speed as it leaves the nozzle?

Answer 1

$t=t_1+t_2,$

$t_1=\frac vg,$

$t_2=\frac {\sqrt{v^2+2gh}}g,$

$v=\frac{gt}2-\frac ht=12~\frac ms.$