Answer to Question #301442 in Mechanics | Relativity for Jhonard

Question #301442

Calculate the specific weight, specific mass, specific volume and specific gravity of a liquid having a volume of 5 cubic meters and its weight is 35 kilo newton

1
Expert's answer
2022-02-23T12:11:30-0500

Answer

Weight of liquid

W=35KNW=35KN

So it's mass becomes

M=Wg=350009.81=3567.8KgM=\frac{W}{g}\\=\frac{35000}{9.81}\\=3567.8Kg

Volume

V=5m3V=5m^3

So

Specific weightγ=WV=350005=7000N/m3Specific \space weight \\\gamma=\frac{W}{V}\\=\frac{35000}{5}\\=7000N/m^3

Specific mass

M=3567.8Kg

Density

ρ=MV=3567.85=711.54Kg/m3\rho =\frac{M}{V}\\=\frac{3567.8}{5}\\=711.54Kg/m^3

Specific volume

v=VM=53567.8=0.0014m3/kgv=\frac{V}{M}\\=\frac{5}{3567.8}\\=0.0014m^3/kg


Specific gravity

Sg=γγat4°C=7.0009.81=0.71Sg=\frac{\gamma}{\gamma_{at 4°C}}\\=\frac{7.000}{9.81}\\=0.71



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment