Explanations & Calculations
- The vertical velocity component of the mortar is 200sin45=141.4ms−1
- Then the time of flight is
↑s0t=ut+21at2=141.4t−4.9t2=0st=28.9s
- Its horizontal velocity is 200cos45=141.4ms−1 (say to right → ).
- Now, the easiest method is to consider the relative velocities, take the horizontal velocity of the mortar relative to the tank (stop the tank and add its velocity to the mortar's),
141.4(→)+10(−←)=151.4ms−1
- Then the distance should be
S=ut=151.4ms−1×28.9s=4375.5m
- So there should be that distance in between before the mortar is fired.
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